Source code for lerot.comparison.BalancedInterleave

# This file is part of Lerot.
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# Lerot is free software: you can redistribute it and/or modify
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# KH, 2012/06/19

import argparse

from numpy import asarray, where
from random import randint


from .AbstractInterleavedComparison import AbstractInterleavedComparison
from ..utils import split_arg_str


[docs]class BalancedInterleave(AbstractInterleavedComparison): """Interleave and compare rankers using the original balanced interleave method.""" def __init__(self, arg_str=None): # this check prevents errors from the if statement at #36 if arg_str is None: arg_str = "random" if arg_str.startswith("--"): parser = argparse.ArgumentParser(description="Parse arguments for " "interleaving method.", prog=self.__class__.__name__) parser.add_argument("-s", "--startinglist") args = vars(parser.parse_known_args(split_arg_str(arg_str))[0]) if "startinglist" in args: self.startinglist = args["startinglist"] else: self.startinglist = "random" else: self.startinglist = arg_str
[docs] def interleave(self, r1, r2, query, length): # get ranked list for each ranker (put in assignment var) l1, l2 = [], [] r1.init_ranking(query) r2.init_ranking(query) length = min(r1.document_count(), r2.document_count(), length) for _ in range(length): l1.append(r1.next()) l2.append(r2.next()) # interleave l = [] i1, i2 = 0, 0 if self.startinglist == "random": # pick starting list at random first = randint(0, 1) elif self.startinglist == "fixed": first = 0 else: raise Exception("Unknown starting method '%s' for " "comparison method %s." % (self.startinglist, self.__class__.__name__)) # interleave deterministically while len(l) < length: if (i1 < i2) or (i1 == i2 and first == 0): if l1[i1] not in l: l.append(l1[i1]) i1 += 1 else: if l2[i2] not in l: l.append(l2[i2]) i2 += 1 # for balanced interleave the assignment captures the two original # ranked result lists l1 and l2 return (asarray(l), (asarray(l1), asarray(l2)))
[docs] def infer_outcome(self, l, a, c, query): c = asarray(c) a = (asarray(a[0]), asarray(a[1])) click_ids = where(c == 1)[0] if not len(click_ids): # no clicks, will be a tie return 0 # find minimum rank of the lowest click: k clicks_on_l1 = [] clicks_on_l2 = [] for clicked in click_ids: a1_clicks = where(a[0] == l[clicked]) if len(a1_clicks[0]): clicks_on_l1.append(a1_clicks[0][0]) a2_clicks = where(a[1] == l[clicked]) if len(a2_clicks[0]): clicks_on_l2.append(a2_clicks[0][0]) # lowest click lowest_click = -1 if len(clicks_on_l1) and len(clicks_on_l2): lowest_click = min(max(clicks_on_l1), max(clicks_on_l2)) elif len(clicks_on_l1): lowest_click = max(clicks_on_l1) elif len(clicks_on_l2): lowest_click = max(clicks_on_l2) # get number of clicked documents ranked higher or equal to N # for both lists c1, c2 = 0, 0 for i in click_ids: if where(a[0] == l[i]) <= lowest_click: c1 += 1 if where(a[1] == l[i]) <= lowest_click: c2 += 1 # compare and return outcome return -1 if c1 > c2 else 1 if c2 > c1 else 0